Answer:
Option (B)
Step-by-step explanation:
1). Given function is,
[tex]f(x)=\frac{1}{x-1}+3[/tex]
It the given function 'f' is transformed by a translation of 2 units to the right, the new function will be,
h(x) = f(x - 2)
h(x) = [tex]\frac{1}{(x-2)-1}+3[/tex]
= [tex]\frac{1}{x-3}+3[/tex]
Further the new function is translated by 6 units down,
g(x) = h(x) - 6
g(x) = [tex]\frac{1}{x-3}+3-6[/tex]
= [tex]\frac{1}{x-3}-3[/tex]
Since, transformed function 'g' passes through a point (x, -2),
g(x) = [tex]\frac{1}{x-3}-3[/tex]
-2 = [tex]\frac{1}{x-3}-3[/tex]
3 - 2 = [tex]\frac{1}{x-3}[/tex]
x - 3 = 1
x = 4
Therefore, Option (B) will be the answer.
