Answer: HIJK is a parallelogram because the midpoint of both diagonals is (1,0) , which means the diagonals bisect each other.
Step-by-step explanation:
Given: The coordinates of parallelogram H I J K as
H is at (- 2, 2), point I is at (4, 3), point J is at (4, - 2), and point K is at (- 2, - 3).
Diagonals : HJ and IK [join opposite vertices]
Mid point of HJ = [tex](\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2})[/tex]
[tex]=(\dfrac{-2+4}{2},\dfrac{2+(-2)}{2})=(1,0)[/tex]
i.e. Mid point of HJ = (1,0)
Mid point of IK = [tex](\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2})[/tex]
[tex]=(\dfrac{4+(-2)}{2},\dfrac{3+(-3)}{2})=(1,0)[/tex]
i.e. Mid point of IK = (1,0) =Mid point of HJ
When mid points of both diagonals are equal then that means the diagonals bisect each other.
Thus, HIJK is a parallelogram because the midpoint of both diagonals is (1,0) , which means the diagonals bisect each other.
