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A basketball is shot into the air. Its height is represented by the polynomial equation
h(t) = -16+ + 35t + 5, where h is the height of the basketball at t seconds. What's
the height of the basketball at 1.5 seconds?
18.8 feet
21.5 feet
16.7 feet
1
20.2 feet

Respuesta :

wegnerkolmp2741o

Answer:

21.5

Step-by-step explanation:

h(t) = -16t^2 + 35t + 5,

Let t = 1.5

h(1.5) = -16 (1.5)^2 + 35(1.5) + 5

        =-16 *2.25 +52.5+5

      = -36+57.5

      = 21.5

SweatzerNeedsAnswer
12.5 hope this help you

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