Answer:
[tex]\{(8, 1), (4, 1), (0,1), (-15, 1)\}[/tex]
Step-by-step explanation:
Given
[tex]\{(-4, -6), (-3, -2), (1, -2), (1, 0)\}[/tex]
[tex]\{(-2, -12), (-2, 0), (-2, 4), (-2, 11)\}[/tex]
[tex]\{(0,1), (0, 2), (1, 2), (1, 3)\}[/tex]
[tex]\{(8, 1), (4, 1), (0,1), (-15, 1)\}[/tex]
Required
Determine which is a function
A relation is divided into 2; (x,y)
Where x represents the range and y stands for the domain
For a relation to be a function, the x column must be unique; in other words, there must be only one occurrence of x
Testing each of the given options
A. [tex]\{(-4, -6), (-3, -2), (1, -2), (1, 0)\}[/tex]
Start by splitting the relation into x and y columns
[tex](x,y)[/tex]
[tex](-4, -6)[/tex]
[tex](-3, -2)[/tex]
[tex](1, -2)[/tex]
[tex](1, 0)[/tex]
Notice that the third and fourth relation has the same x value of 1;
Hence, this is not a function
B. [tex]\{(-2, -12), (-2, 0), (-2, 4), (-2, 11)\}[/tex]
Start by splitting the relation into x and y columns
[tex](x,y)[/tex]
[tex](-2, -12)[/tex]
[tex](-2, 0)[/tex]
[tex](-2, 4)[/tex]
[tex](-2, 11)[/tex]
Notice that all relations has the same x value of -2;
Hence, this is also not a function
C. [tex]\{(0,1), (0, 2), (1, 2), (1, 3)\}[/tex]
Start by splitting the relation into x and y columns
[tex](x,y)[/tex]
[tex](0, 1)[/tex]
[tex](0, 2)[/tex]
[tex](1, 2)[/tex]
[tex](1, 3)[/tex]
Notice that the first and second relation has the same x value of 0 and the third and fourth relation has the same x value of 1;
Hence, this is also not a function
D. [tex]\{(8, 1), (4, 1), (0,1), (-15, 1)\}[/tex]
Start by splitting the relation into x and y columns
[tex](x,y)[/tex]
[tex](8, 1)[/tex]
[tex](4, 1)[/tex]
[tex](0, 1)[/tex]
[tex](-15, 1)[/tex]
Notice that relation has the unique x values of 8, 4, 0 and -15
Hence, this relation is a function
