Answer:
Only A is divisible by 24.
Step-by-step explanation:
A number is divisible by 24 if it's divisible by both 3 and 8.
Numbers are divisible by 3 if all their digits add to a multiple of 3, and numbers are divisible by 8 if the last 3 digits are divisible by 8.
Let's look at A, 13944. The numbers add up to [tex]1+3+9+4+4=21[/tex], which is divisible by 3.
944 is divisible by 8, and it makes 118.
So A works.
B is 15746.
[tex]1+5+7+4+6=23[/tex], so this won't work as 23 isn't divisible by 3.
C is 15966.
[tex]1+5+9+6+6=27\div3=9[/tex], so this works for 3 but let's check 8.
[tex]966\div8=120.75[/tex] so it's not divisible by 8, therefore not divisible by 24.
D is 16012.
[tex]1+6+0+1+2=10[/tex] and 10 isn't divisible by 3, so it doesn't work.
Hope this helped!
