In rectangle ABCD, point E lies half way between sides AB and CD and halfway between sides AD and BC. If AB=10 and BC=2, what is the area of the shaded region? Answer as a decimal, if necessary. Little confused on this one.

In rectangle ABCD point E lies half way between sides AB and CD and halfway between sides AD and BC If AB10 and BC2 what is the area of the shaded region Answer class=

Respuesta :

Answer:

10 units²

Step-by-step explanation:

Consider the unshaded region to consists of 2 triangles, ∆AED and ∆BEC, which are both of equal dimensions. Their bases and heights are both the same. Both triangles are embedded inside a rectangle ABCD.

Area of the shaded region = Area of rectangle - area of the 2 triangles.

Area of rectangle = l*w

l = 10

w = 2

[tex] Area_R = 10*2 = 20 units^2 [/tex]

Area of the 2 triangles = 2(½*b*h)

b = 2

h = 5

[tex]Area_T = 2(\frac{1}{2}*2*5)[/tex]

[tex] Area_T = 1*2*5 = 10 units^2 [/tex]

Area of shaded region = 20 - 10 = 10 units²

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