In rectangle ABCD, point E lies half way between sides AB and CD and halfway between sides AD and BC. If AB=10 and BC=2, what is the area of the shaded region? Answer as a decimal, if necessary. Little confused on this one.
Answer:
10 units²
Step-by-step explanation:
Consider the unshaded region to consists of 2 triangles, ∆AED and ∆BEC, which are both of equal dimensions. Their bases and heights are both the same. Both triangles are embedded inside a rectangle ABCD.
Area of the shaded region = Area of rectangle - area of the 2 triangles.
Area of rectangle = l*w
l = 10
w = 2
[tex] Area_R = 10*2 = 20 units^2 [/tex]
Area of the 2 triangles = 2(½*b*h)
b = 2
h = 5
[tex]Area_T = 2(\frac{1}{2}*2*5)[/tex]
[tex] Area_T = 1*2*5 = 10 units^2 [/tex]
Area of shaded region = 20 - 10 = 10 units²