Answer:
C
Step-by-step explanation:
let hypotenuse of triangle with 60°=y
[tex]\frac{8\sqrt{2}}{y} =sin ~60\\8 \sqrt{2}=y \times \frac{\sqrt{3}}{2} \\y=\frac{16 \sqrt{2}}{\sqrt{3}} =\frac{16 \sqrt{6}}{3}[/tex]
