Answer:
[tex]2\sqrt{3}+3[/tex]
Step-by-step explanation:
[tex]$\frac{3}{2 \sqrt 3 - 3}$[/tex]
Rationalize the fraction.
[tex]$\frac{3}{2 \sqrt 3 - 3}\cdot \frac{2 \sqrt 3 + 3}{2 \sqrt 3 + 3} =\frac{6\sqrt{3}+9 }{12-9} =\frac{6\sqrt{3}+9 }{3} =2\sqrt{3}+3 $[/tex]
Note that I used the positive signal because we would have a difference of squares.
