Answer:
The probability is [tex]P(2) = 0.426[/tex]
Step-by-step explanation:
From the question we are told that
The probability of success is [tex]p = 0.26[/tex]
The number of hits is n = 7
Generally this probability follows a binomial distribution given there can only be two outcome i.e the probability of success and the probability of failure
The probability of failure is [tex]q = 1- p[/tex]
substituting values
[tex]q = 1 - 0.26[/tex]
[tex]q = 0.74[/tex]
Now the probability of exactly 2 hits in his next 7 at bats is mathematically evaluated as
[tex]P(2) = \left n} \atop {}} \right. C_2 *p^{2} * q^{n- 2}[/tex]
substituting values
[tex]P(2) = \left 7} \atop {}} \right. C_2 *p^{2} * q^{7- 2}[/tex]
Here [tex]\left 7} \atop {}} \right. C_2[/tex] means 7 combination 2 and using a calculator(reference calculator soup website) to compute, the value obtained is
[tex]\left 7} \atop {}} \right. C_2 =21[/tex]
So
[tex]P(2) = 21 *(0.26)^{2} * (0.74)^{5}[/tex]
[tex]P(2) = 0.426[/tex]
