Step-by-step explanation:
[tex] {9}^{ - 53} . {9}^{37} [/tex]
To solve this question we use the rules of indices
Since the bases are the same and are multiplying we add the exponents using the formula
[tex] {a}^{b} \times {a}^{c} = {a}^{b + c} [/tex]
So for the above question we have
[tex] {9}^{ - 53} \times {9}^{37} = {9}^{ - 53 + 37} [/tex]
We have the final answer as
[tex] {9}^{ - 16} [/tex]
Which is the same as
[tex] \frac{1}{ {9}^{16} } [/tex]
Hope this helps you
