Respuesta :
Answer:
We conclude that the proportion of families with children under the age of 18 who eat dinner together seven nights a week has decreased.
Step-by-step explanation:
The complete question is: In a previous poll, 46% of adults with children under the age of 18 reported that their family ate dinner together seven nights a week. Suppose that, in a more recent poll, 480 of 1081 adults with children under the age of 18 reported that their family ate dinner together seven nights a week. Is there sufficient evidence that the proportion of families with children under the age of 18 who eat dinner together seven nights a week has decreased? Use the [tex]\alpha[/tex] = 0.10 significance level.
Let p = population proportion of families with children under the age of 18 who eat dinner together seven nights a week.
So, Null Hypothesis, : p 46% {means that the proportion of families with children under the age of 18 who eat dinner together seven nights a week has increased or remains same}
Alternate Hypothesis, : p < 46% {means that the proportion of families with children under the age of 18 who eat dinner together seven nights a week has decreased}
The test statistics that will be used here is One-sample z-test for proportions;
T.S. = ~ N(0,1)
where, [tex]\hat p[/tex] = sample proportion of families = [tex]\frac{480}{1081}[/tex] = 0.44
n = sample of adults with children under the age of 18 = 1081
So, the test statistics =
= -1.32
The value of z-statistics is -1.32.
Also, the P-value of the test statistics is given by;
P-value = P(Z < -1.32) = 1 - P(Z [tex]\leq[/tex] 1.32)
= 1 - 0.9066 = 0.0934
Since the P-value of our test statistics is less than the level of significance as 0.0934 < 0.10, so we have sufficient evidence to reject our null hypothesis as the test statistics will fall in the rejection region.
Therefore, we conclude that the proportion of families with children under the age of 18 who eat dinner together seven nights a week has decreased.
