The conic section chosen is a parabola, and the attributes for graphing of
a parabola as well as the standard form of the equation are as follows;
- Part A: The attribute necessary to graph the equation of the parabola are three points, including, the vertex, the y-intercept and the image of the reflection of the y-intercept across the axis of symmetry.
- Part B: The equation in standard form is x = -0.25·y² + y + 3
Reasons:
Part A:
The equation of the conic section of a parabola is; (x - 3)² = 12·(y - 2)
The vertex form of the equation of a parabola is; y = a·(x - h)² + k
Where (h, k) = The vertex
Rearranging the given equation gives;
(x - 3)² = 12·y - 24
12·y - 24 = (x - 3)²
12·y = (x - 3)² + 24
[tex]\displaystyle y = \frac{1}{12} \cdot \left(x - 3\right)^2 + \frac{24}{12} = \frac{1}{12} \cdot \left(x - 3\right)^2 + 2[/tex]
[tex]\displaystyle y = \frac{1}{12} \cdot \left(x - 3\right)^2 + 2[/tex]
Therefore, the vertex of the parabola, (h, k) = (3, 2)
At the y-intercept, x = 0, which gives;
[tex]\displaystyle y = \frac{1}{12} \cdot \left(0 - 3\right)^2 + 2 = \frac{9}{12} + 2 = 2+\frac{3}{4}[/tex]
[tex]\displaystyle y = 2+\frac{3}{4} = 2.75[/tex]
The y-intercept = (0, 2.75)
The x-intercept is given at the point where y = 0, which gives;
(x - 3)² = 12·(0 - 2) = -24
x - 3 = √(-24) = An imaginary number
Therefore, the graph has no x-intercept
Given that a parabola is symmetrical about the vertex, we have a third
point on the parabola at the image of the y-intercept reflected across the
axis of symmetry as follows;
The y-intercept (0, 2.75) is 3 units to the left of the axis of symmetry, x = 3,
therefore, the third point will be 3 units to the right of the axis of symmetry
at the point (3 + 3, 2.75) = (6, 2.75)
Therefore, using the three points, (0, 2.75), (3, 2), and (6, 2.75), the curve
representing the parabola, (x - 3)² = 12·(y - 2), can be drawn.
Please find attached the graph of the parabola created with MS Excel
Part B; Given the attributes of the parabola; Vertex: (4, 2) and focus: (3, 2), we have;
The focus of a parabola is the point (h + p, k)
Where, (h, k) = The vertex
Therefore, by comparison, we have;
(h, k) = (4, 2)
h + p = 3
Therefore;
4 + p = 3
p = 3 - 4 = -1
The vertex form of the equation of the parabola is; (y - k)² = 4·p·(x - h)
Therefore, we get;
(y - 2)² = 4 × (-1) × (x - 4) = -4·(x - 4)
y² - 4·y + 4 = 16 - 4·x
4·x = 16 - (y² - 4·y + 4) = -y² + 4·y + 12
Which gives, the standard form as follows;
[tex]\displaystyle x = -\frac{y^2}{4} + y + 3 = -0.25 \cdot y^2 + y + 3[/tex]
- Standard form of the the equation of the parabola; x = -0.25·y² + y + 3
Learn more about the graph of a parabola here:
https://brainly.com/question/2489929
