Respuesta :

Answer:

c

Step-by-step explanation:

x³ - y³ ← is a difference of cubes and factors as

x³ - y³ = (x - y)(x² + xy + y²)

Given

[tex]\frac{x}{y}[/tex] + [tex]\frac{y}{x}[/tex] = - 1

Multiply through by xy to clear the fractions

x² + y² = - xy ← substitute into second factor of expansion

x³ - y³ = (x - y)(- xy + xy) = (x - y) × 0 = 0 → c

Answer:

The answer is C. 0

Step-by-step explanation:

since

[tex] \frac{x}{y} + \frac{y}{x } = - 1[/tex]

we multiply both sides by xy to cancel their denominators and multiply -1 by xy

so we have

[tex]xy( \frac{x}{y}) + xy( \frac{x}{y} ) = xy \times - 1[/tex]

we get our answer as

[tex] {x}^{2} + {y}^{2} = - xy[/tex]

we were given the difference of cubes that is

[tex] {x}^{3} - {y}^{3} [/tex]

which is =

[tex](x - y)( {x}^{2} + xy + {y}^{2} )[/tex]

so since,

[tex] {x}^{2} + {y}^{2} = - xy[/tex]

we substitute,

[tex](x - y)( - xy + xy) = (x - y)(0) = 0[/tex]

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