Answer:
Step-by-step explanation:
Let equal sides of an isosceles triangle = a inches
Base = [tex]\frac{1}{2}a+2[/tex] inches
Perimeter = 32 inches
a + a + [tex]\frac{1}{2}a+2[/tex] = 32
[tex]2a + \frac{1}{2}a+2 = 32\\\\\frac{2a*2}{1*2}+\frac{1}{2}a+2=32\\\\\frac{4a}{2}+\frac{1}{2}a+2=32\\\\\frac{5}{2}a+2 = 32\\\\[/tex]
Subtract 2 from both sides
[tex]\frac{5}{2}a=32-2\\\\\frac{5}{2}a=30\\\\a=30*\frac{2}{5}\\\\a=6*2[/tex]
a = 12 inches
base = [tex]\frac{1}{2}*12+2[/tex]
= 6 + 2
Base = 8 inches
