Answer:
[tex]g^{-1}(x)=-6-\frac{x}{3} =-\frac{x}{3} -6[/tex]
Step-by-step explanation:
First assign a letter "y" to g(x) and get rid of parenthesis on the right:
[tex]g(x)=-3\,(x+6)\\y=-3x-18[/tex]
Now, solve for "x":
[tex]3x=-18-y\\x=\frac{-18-y}{3}\\x=-6-\frac{y}{3}[/tex]
now replace y with x, and call x : [tex]g^{-1}(x)[/tex]
[tex]x=-6-\frac{y}{3} \\g^{-1}(x)=-6-\frac{x}{3}[/tex]
