Answer:
[tex] \boxed{12 \sqrt{2} }[/tex]
Step-by-step explanation:
Isosceles triangle are those triangle which have two equal sides.
Perpendicular ( p ) = 12 inches
Base ( b ) = 12 inches
Hypotenuse ( h ) = ?
Now,Using Pythagoras theorem,
[tex] \mathsf{ {h}^{2} = {p}^{2} + {b}^{2} }[/tex]
Plug the values
[tex] \mathsf{ {h}^{2} = {12}^{2} + {12}^{2} }[/tex]
Evaluate the power
[tex] \mathsf{ {h}^{2} = 144 + 144}[/tex]
Calculate the sum
[tex] \mathsf{ {h}^{2} = 288}[/tex]
Squaring on both sides
[tex] \mathsf{h = 12 \sqrt{2} }[/tex]
Hope I helped!
Best regards!
