Answer: f(x) will have vertical asymptotes at x=-2 and x=2 and horizontal asymptote at y=3.
Step-by-step explanation:
Given function: [tex]f(x)=\dfrac{3x^2}{x^2-4}[/tex]
The vertical asymptote occurs for those values of x which make function indeterminate or denominator 0.
i.e. [tex]x^2-4=0\Rightarrow\ x^2=4\Rightarrow\ x=\pm2[/tex]
Hence, f(x) will have vertical asymptotes at x=-2 and x=2.
To find the horizontal asymptote , we can see that the degree of numerator and denominator is same i.e. 2.
So, the graph will horizontal asymptote at [tex]y=\dfrac{\text{Coefficient of }x^2\text{ in numerator}}{\text{Coefficient of }x^2\text{ in denominator}}[/tex]
i.e. [tex]y=\dfrac{3}{1}=3[/tex]
Hence, f(x) will have horizontal asymptote at y=3.
