Answer:
[tex]\large \boxed{\sf \bf \ \ y=3x^2-6x-1 \ \ }[/tex]
Step-by-step explanation:
Hello, please consider the following.
We can read from the graph that the vertex is (1,-4) , it means that the equation is, a being a real number.
[tex]y=a(x-1)^2-4[/tex]
And the point (0,-1) is on the graph so we can write.
[tex]a\cdot 1^2-4=-1 \\\\a-4+4=-1+4\\\\a = 3[/tex]
So the equation is.
[tex]y=3(x-1)^2-4\\\\=3(x^2-2x+1)-4\\\\=3x^2-6x+3-4\\\\=3x^2-6x-1\\\\=\boxed{3}x^2\boxed{-6}x\boxed{-1}[/tex]
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
