Answer: 54.29%
Step-by-step explanation:
Given: The probability that they will win both games is 38%.
i.e. P( both games will win) =0.38
The probability that they will win just the first game is 70%.
P(first game will win) = 0.70
To find : P(second game will win| first game will win)
Using formula: [tex]P(B|A)=\dfrac{P(\text{both A and B})}{P(A)}[/tex]
So, P(second game will win| first game will win) = [tex]\dfrac{\text{ P( both games will win)}}{\text{P(first game will win)}}[/tex]
[tex]=\frac{0.38}{0.70}\approx0.5429=54.29\%[/tex]
Hence, the required probability = 54.29%
