The given line segment has a midpoint at (-1, -2).
What is the equation, in slope-intercept form, of the
perpendicular bisector of the given line segment?
ch
4
3
O y=-4x - 4
O y = -4x - 6
O y=x-4
2
1
х
5 4 -3 -2 -11
61,-2)
Oy=+x-6
234
(3.-1).
-3
(-5, 3)
w5

The given line segment has a midpoint at 1 2 What is the equation in slopeintercept form of the perpendicular bisector of the given line segment ch 4 3 O y4x 4 class=

Respuesta :

Answer:

  y = -4x -6

Step-by-step explanation:

The given segment has a rise if 1 for a run of 4, so a slope of ...

  m = rise/run = 1/4

The desired perpendicular has a slope that is the negative reciprocal of this:

  m = -1/(1/4) = -4

A point that has a rise of -4 for a run of 1 from the given midpoint is ...

  (-1, -2) +(1, -4) = (0, -6) . .  . . . . . the y-intercept of the bisector

So, our perpendicular bisector has a slope of m=-4 and a y-intercept of b=-6. Putting these in the slope-intercept form equation, we find the line to be ...

  y = mx +b

  y = -4x -6

Ver imagen sqdancefan

The equation of the line in slope intercept form is y = -4x -6

What is a linear equation?

A linear equation is in the form:

y = mx + b

Where y,x are variables, m is the rate of change and b is the y intercept.

Two lines are perpendicular of the product of the slope is -1

The line passes through the point (-5, -3) and (3, -1). Hence:

Slope = (-1 - (-3)) / (3 - (-5)) = 1/4

The slope of the line perpendicular to this line is -4 (-4 *  1/4 = -1).

The line passes through (-1, -2), hence:

y - (-2) = -4(x - (-1))

y + 2 = -4(x + 1)

y = -4x -6

The equation of the line in slope intercept form is y = -4x -6

Find out more on linear equation at: https://brainly.com/question/14323743

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