Answer:
[tex]\Large \boxed{\sf \bf \ \ y=4(x-5)^2-12 \ \ }[/tex]
Step-by-step explanation:
Hello, please consider the following.
[tex]\dfrac{1}{4}(y + 12) = (x - 5)^2\\\\\text{We multiply by 4 both sides of the equation.}\\\\y+12=4(x-5)^2\\\\\text{We subtract 12 from both sides of the equation.}\\\\y=4(x-5)^2-12=a(x-h)^2+k[/tex]
So a = 4, h = 5 and k = 12
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
