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The diagonals of rhombus WXYZ intersect at point P. If WP = 12 and XP = 5, find the perimeter of the rhombus.

A.13
B.17
C.26
D.52

The diagonals of rhombus WXYZ intersect at point P If WP 12 and XP 5 find the perimeter of the rhombus A13 B17 C26 D52 class=

Respuesta :

Answer: 52

Use the pythagorean theorum to calculate WX, since it's a rhombus, all sides are equal, multiply by four, finished.

Answer with explanation:

WP=12 units

XP=5 units

Diagonals of rhombus bisect each other at right angles.as well as All sides of Rhombus are equal.

∠WPX=∠XPY=∠ZPY=∠WPZ=90°

Using Pythagoras theorem In Δ WPX

WX²=WP²+PX²

     =12²+5²

WX²=144+25

WX²=169

WX=√169

WX=13 units

Perimeter of Rhombus WXYZ=4 × Side length (WX)

                             =4 × 13

                             = 52 Units

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