Respuesta :
K = Kevin's age
D = Daniel's age
K = 3D
K - 4 = 5(D - 4)
Plug in 3D for the K values in the second equation.
3D - 4 = 5(D - 4) Use the Distributive Property
3D - 4 = 5D - 20 Add 4 to both sides
3D = 5D - 16 Subtract 5D from both sides
-2D = -16 Divide both sides by -2
D = 8
Now, plug that D value into the original equation.
K = 3D Plug in the D value
K = 3(8) Multiply
K = 24
Finally, you can double check your math.
4 years ago, Daniel would've been 4 and Kevin would be 20, so Kevin would've been 5 times as old as Daniel. And 8 x 3 = 24.
So, Kevin is 24.
D = Daniel's age
K = 3D
K - 4 = 5(D - 4)
Plug in 3D for the K values in the second equation.
3D - 4 = 5(D - 4) Use the Distributive Property
3D - 4 = 5D - 20 Add 4 to both sides
3D = 5D - 16 Subtract 5D from both sides
-2D = -16 Divide both sides by -2
D = 8
Now, plug that D value into the original equation.
K = 3D Plug in the D value
K = 3(8) Multiply
K = 24
Finally, you can double check your math.
4 years ago, Daniel would've been 4 and Kevin would be 20, so Kevin would've been 5 times as old as Daniel. And 8 x 3 = 24.
So, Kevin is 24.
k=kevin age
d=daniel ae
k is 3 times d
k=3d
4 years ago (k-4 and d-4)
kevin was 5 times as old as dan
k-4=5(d-4)
we have
k=3d
and
k-4=5(d-4)
sub 3d for k in second euaiton
3d-4=5(d-4)
3d-4=5d-20
minus 3d both sides
-4=2d-20
add 20 both sides
16=2d
divide 2
8=d
sub back
k=3d
k=3(8)
k=24
kevin is 24
d=daniel ae
k is 3 times d
k=3d
4 years ago (k-4 and d-4)
kevin was 5 times as old as dan
k-4=5(d-4)
we have
k=3d
and
k-4=5(d-4)
sub 3d for k in second euaiton
3d-4=5(d-4)
3d-4=5d-20
minus 3d both sides
-4=2d-20
add 20 both sides
16=2d
divide 2
8=d
sub back
k=3d
k=3(8)
k=24
kevin is 24