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A large population of laboratory animals has been allowed to breed randomly for a number of generations. After several generations, 49% of the animals display a recessive trait (bb), the same percentage as at the beginning of the breeding program. The rest of the animals show the dominant phenotype, with heterozygotes indistinguishable from the homozygous dominants.

What is the frequency of allele b in the gene pool?

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PrinceBrainly
Hi there!!!!!!!! :DDDD

How do I solve this?A large population of laboratory animals has been allowed to breed randomly for a number of generations. After several generations, 49% of the animals display a recessive trait (bb), the same percentage as at the beginning of the breeding program. The rest of the animals show the dominant phenotype, with heterozygotes indistinguishable from the homozygous dominants.

What is the frequency of allele b in the gene pool?

Answer: 0 .70
marianaegarciaperedo

According to Hardy-Weinberg equilibrium, by knowing the value of the recessive genotypic frequency (q²), we can get the allelic frequencies (p and q). In this case, the frequency of allele b in the gene pool is q = 0.7.

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To answer this question, we need to pay attention to the given information.

So, when the statement says  

...laboratory animals has been allowed to breed randomly...and After several generations, 49% of the animals display a recessive trait (bb), the same percentage as at the beginning of the breeding program...

suggests that the population is under Hardy-Weinberg equilibrium.

According to Hardy-Weinberg,

→ The allelic frequencies in a locus are represented as p and q,

  • p the dominant allelic frequency
  • q the recessive allelic frequency

→ The genotypic frequencies after one generation are

  • p²  ⇒ H0m0zyg0us dominant,
  • 2pq  ⇒ Heter0zyg0us,
  • q²  ⇒ H0m0zyg0us recessive.

→ Populations in H-W equilibrium will get the same allelic frequencies generation after generation.

→ The sum of allelic frequencies equals 1 ⇒ p + q = 1.

→ The sum of genotypic frequencies equals 1 ⇒ p² + 2pq + q² = 1

Now, we need to find the frequency of the recessive allele, b.

So far, we have the genotypic frequency of the recessive trait ⇒ 49% = 0.49

We know that q² is the frequency of the h0m0zyg0ous recessive genotype and q is the frequency of the recessive allele.

If q² = 0.49

then q = √q² = √0.49 = 0.7

So, the frequency of allele b in the gene pool is q = 0.7.

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