Answer:
[tex]a=\frac{10x-35}{2x-7}[/tex]
Step-by-step explanation:
We have been given an equation [tex]10x-35+3ax=5ax-7a[/tex]. We are asked to solve the given equation for 'a'.
Switch sides:
[tex]5ax-7a=10x-35+3ax[/tex]
[tex]5ax-3ax-7a=10x-35+3ax-3ax[/tex]
[tex]2ax-7a=10x-35[/tex]
Factor out a:
[tex]a(2x-7)=10x-35[/tex]
Divide both sides by [tex](2x-7)[/tex]:
[tex]\frac{a(2x-7)}{(2x-7)}=\frac{10x-35}{(2x-7)}[/tex]
[tex]a=\frac{10x-35}{2x-7}[/tex]
Therefore, our required equation would be [tex]a=\frac{10x-35}{2x-7}[/tex].
