Graph the first six terms of a sequence where a1=4 and r=2.

The standard formula for geometric sequence is an = a1 * r^(n-1) where r is the geometric factor and n is an integer. In this problem, upon substitution, an = 4*2^(n-1). We graph this in excel attached below. The graph is an exponential one as projected.

Answer Link

onyebuchinnaji onyebuchinnaji · Answer 2 · 2022-07-07T12:32:08+02:00

The graph of the first six sequence of the geometric progression is attached to this solution.

First sequence of the progression

a₁ = 4

Second sequence of the progression

general sequence formula is given as;

[tex]a_n = a_1r^{n- 1}[/tex]

a₂ = 4 x 2

a₂ = 8

Third sequence of the progression

a₃ = 4 x 2²

a₃ = 16

Fourth sequence of the progression

a₄ = 4 x 2³

a₄ = 32

Fifth sequence of the progression

a₅ = 4 x 2⁴

a₅ = 64

Sixth sequence of the progression

a₆ = 4 x 2⁵

a₆ = 128

The graph of the first six sequence of the geometric progression is attached to this solution.

Learn more about geometric sequence here: https://brainly.com/question/1509142

#SPJ5