Using trigonometric function concepts, it is found that the function defined on the graph is:
D. y = csc x
What is the tangent, cotangent, secant and cosecant of an angle?
- The tangent of an angle [tex]\theta[/tex] is given by:
[tex]\tan{\theta} = \frac{\sin{\theta}}{\cos{\theta}}[/tex]
- The cotangent is given by:
[tex]\cot{\theta} = \frac{\cos{\theta}}{\sin{\theta}}[/tex]
The secant is given by:
[tex]\sec{\theta} = \frac{1}{\cos{\theta}}[/tex]
The cosecant is given by:
[tex]\csc{\theta} = \frac{1}{\sin{\theta}}[/tex]
In this problem, the discontinuities are at [tex]\pm k\pi, k = 0, 1, 2, \cdots[/tex], which implies that the term at the denominator is a sine.
At [tex]x = \frac{\pi}{4} \approx 0.785[/tex], we have that [tex]y \neq 1[/tex], which means that the function is the cosecant, as:
[tex]\cot{\frac{\pi}{4}} = \frac{\cos{\frac{\pi}{4}}}{\sin{\frac{\pi}{4}}} = 1[/tex]
[tex]\csc{\theta} = \frac{1}{\sin{\theta}} = \frac{1}{\frac{\sqrt{2}}{2}} = \sqrt{2}[/tex]
Hence, option D is correct.
You can learn more about trigonometric functions at https://brainly.com/question/18055768