Respuesta :
If the rock has 12.5 % of its original amount of potassium-40 remaining in it, this has a half-life of 1.25 billion years, the rock was formed approximately 3.75 billion years ago. The correct answer is C.
Answer : The correct option is, (C) 3.75 billion years ago.
Explanation :
Half-life = 1.25 billion years
First we have to calculate the rate constant, we use the formula :
[tex]k=\frac{0.693}{t_{1/2}}[/tex]
[tex]k=\frac{0.693}{1.25\text{ years}}[/tex]
[tex]k=0.554\text{ billion years}^{-1}[/tex]
Now we have to calculate the time passed.
Expression for rate law for first order kinetics is given by:
[tex]t=\frac{2.303}{k}\log\frac{a}{a-x}[/tex]
where,
k = rate constant = [tex]0.554\text{ billion years}^{-1}[/tex]
t = time passed by the sample = ?
a = let initial amount of the reactant = X g
a - x = amount left after decay process = [tex]12.5\% \times (x)=\frac{12.5}{100}\times (X)=0.125Xg[/tex]
Now put all the given values in above equation, we get
[tex]t=\frac{2.303}{0.554}\log\frac{X}{0.125X}[/tex]
[tex]t=3.75\text{ billion years}[/tex]
Therefore, the time ago the rock formed was [tex]3.75\text{ billion years}[/tex]