To prepare an acetic acid/acetate buffer, a technician mixes 30.6 mL of 0.0880 acetic acid and 21.6 mL of 0.110 sodium acetate in a 100 mL volumetric flask and then fills with water to the 100 mL mark. How many moles of acetic acid are present in this buffer?

Respuesta :

Answer: There are 0.00269 moles of acetic acid in buffer.

Explanation:

To calculate the number of moles for given molarity, we use the equation:

[tex]\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution in ml}}[/tex]     .....(1)

Molarity of acetic acid solution = 0.0880 M

Volume of solution = 30.6 mL

Putting values in equation 1, we get:

[tex]0.0880M=\frac{\text{Moles of acetic acid}\times 1000}{30.6ml}\\\\\text{Moles of acetic acid}=\frac{0.0880\times 30.6}{1000}=0.00269mol[/tex]

Thus there are 0.00269 moles of acetic acid in buffer.

There are 0.00269 moles of acetic acid in buffer.

Calculation for number of moles:

To calculate the number of moles for given molarity, we use the equation:

Molarity = Number of moles of solute * 1000 / Volume of solution .....(1)

Given:

Molarity of acetic acid solution = 0.0880 M

Volume of solution = 30.6 mL

On substituting the values:

0.0880 = Number of moles of solute * 1000 / 30.6

Number of moles of solute = 0.0880 *30.6 / 1000

Number of moles of solute = 0.00269 moles

Thus, there are 0.00269 moles of acetic acid in buffer.

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