A gargoyle statue falls off the side of a building from a height of 75 m. (Assume no air resistance.) How fast is the statue moving when it reaches the ground?​

Respuesta :

Answer:

About 38.34 m/s

Explanation:

[tex]v_f^2=v_o^2+2ad[/tex]

Since there is no intial velocity, and the acceleration due to gravity on Earth is about 9.8 m/s^2:

[tex]v_f^2=2(9.8)(75) \\\\v_f^2=1470 \\\\v_f=\sqrt{1470}\approx 38.34m/s[/tex]

Hope this helps!

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