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Melinda sold packages of gourmet coffee, x, and pastries, y, at a school fundraiser. The packages of coffee sold for $6 each and pastries sold for $4 each. At the end of the fundraiser, she had sold 2 more packages of coffee than pastries and made $72 in total sales for the fundraiser. Create and graph system of linear equations that model this situation.

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Answer:

Please find the attached graph

Melinda sold 8 packages of coffee and 6 packages of pastries

Step-by-step explanation:

The parameters given are;

Number of Packages of coffee = x

Number of Packages of pastries = y

Price of each package of coffee = $6

Price of each package of coffee = $4

Number of packages of packages of coffee sold = 2 more than packages of packages pastries sold

x = 2 + y

y = x - 2................(1)

Sum of money made in the fundraiser = $72

∴ x × $6 + y × $4 = $72

y = ($72 - x × $6)/$4 = 18 - 3/2·x

y = 18 - 3/2·x.........(2)

The solution is

x - 2 = 18 - 3/2·x

x + 3/2 = 18 + 2 = 20

5/2·x = 20

x = 2/5×20 = 8

y = x - 2 = 8 - 2 = 6

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