Answer:
The large sample size 'n' = 384.16
Step-by-step explanation:
Explanation:-
Given Margin of error = 4
Given Population standard deviation(σ) = 40
The margin of error is determined by
[tex]M.E = Z_{0.05} \frac{S.D}{\sqrt{n} }[/tex]
[tex]4 = 1.96 \frac{40}{\sqrt{n} }[/tex]
Cross multiplication , we get
[tex]\sqrt{n} = \frac{40 X 1.96}{4}[/tex]
√ n = 19.6
squaring on both sides , we get
n = 384.16
Final answer:-
The large sample size 'n' = 384.16
