Answer:
0.894
Step-by-step explanation:
Data provided in the question
BC length = 17.89 unit
DC length = 16 unit.
Now, we have to compute the angle y with the help of the cosine function;
Cosine defines the ratio between the right angle adjacent side and the hypotenuse
[tex]\cos = \frac{Adjacent side}{Hpotenuse}[/tex]
As per the triangle BDC;
Hypotenuse = BC =17.89 unit
And, the Adjacent side = 16 units
So;
[tex]\cos y =\frac{16}{17.89} =0.894354388[/tex]
[tex]y =\cos^{-1} (0.894354388) = 26.57^{\circ} (nearest\ to\ hundredths\ place)[/tex]
Now, determine the value of angle x
In right angle ΔABC;
As we know that
The three angles sum is 180 degrees
So,
[tex]\angle A + \angle B +\angle C =180^{\circ} ....(1)[/tex]
According to the given figure
[tex]\angle B=90^{\circ}, \angle A =x^{\circ}[/tex]
and
[tex]\angle C =y=26.57^{\circ}[/tex]
Now Substitute these in (1) for solving the angle x;
[tex]x^{\circ}+90^{\circ}+y^{\circ} =180^{\circ}[/tex]
or
[tex]x^{\circ}+90^{\circ}+26.57^{\circ} =180^{\circ}[/tex]
or
[tex]x^{\circ}+116.57^{\circ} =180^{\circ}[/tex]
[tex]x^{\circ}=180^{\circ} - 116.57^{\circ}=63.43^{\circ}[/tex]
Finally we have to determine the value of sin x;
Hence,
The value of [tex]\sin 63.43 =0.89438856[/tex]
or
= 0.894
