Answer: see below
Step-by-step explanation:
[tex]sin\ \theta=\dfrac{y}{r}=\dfrac{84}{85}\qquad \qquad \text{Quadrant I implies both x and y are positive}\\\\\\\\\text{Use Pythagorean Theorem to find x:}\\x^2+\ y^2=r^2\\x^2+84^2=85^2\\x^2\qquad =85^2-84^2\\x^2\qquad =169\\.\qquad x =13\\[/tex]
Input x = 13, y = 84, r = 85 into the trig functions:
[tex]\sin\ \theta=\dfrac{y}{r}=\large\boxed{\dfrac{84}{85}}\qquad \qquad \qquad \csc \theta=\dfrac{r}{y}=\large\boxed{\dfrac{85}{84}}\\\\\\\\\cos\ \theta=\dfrac{x}{r}=\large\boxed{\dfrac{13}{85}}\qquad \qquad \qquad \sec \theta=\dfrac{r}{x}=\large\boxed{\dfrac{85}{13}}\\\\\\\\\tan\ \theta=\dfrac{y}{x}=\large\boxed{\dfrac{84}{13}}\qquad \qquad \qquad \cot \theta=\dfrac{x}{y}=\large\boxed{\dfrac{13}{84}}[/tex]
