Answer:
A
Step-by-step explanation:
We want to simplify the product [tex](3y^{-4})(2y^{-4})[/tex].
First, notice that both terms have a power with base y, so by the properties of exponents, we can combine the two [tex]y^{-4}[/tex] into one by adding their exponents:
[tex]y^{-4}*y^{-4}=y^{-4+(-4)}=y^{-8}[/tex]
Now, let's multiply the 3 and 2:
3 * 2 = 6
So far, we have [tex]6y^{-8}[/tex]. However, we have a negative exponent that we want to make positive. Remember another property of exponents that when we have a negative exponent, we can make it positive by taking the reciprocal of it. Thus, [tex]y^{-8}[/tex] becomes [tex]\frac{1}{y^8}[/tex].
Hence, our answer is [tex]6*\frac{1}{y^8}=\frac{6}{y^8}[/tex], or A.
~ an aesthetics lover
