Respuesta :
The correct answer is: c.)–6, 0, –4
This is due to the following:
f(x) = 0
[tex]x^{3}+10x^{2}+24x = 0 [/tex]
[tex]x · (x^{2} + 10x + 24) = 0 [/tex]
[tex]x^{2} + 10x - 24 = 0 [/tex]
[tex]x = \frac{- 10 +- \sqrt{10^{2}- 4 x 1 x 24}} {2}[/tex]
[tex]x = \frac{- 10 + 2} {2} = -4[/tex]
[tex]x = \frac{- 10 - 2} {2} = -6[/tex]
[tex]x = -6[/tex]
[tex]x = -4[/tex]
[tex]x = 0[/tex]
This is due to the following:
f(x) = 0
[tex]x^{3}+10x^{2}+24x = 0 [/tex]
[tex]x · (x^{2} + 10x + 24) = 0 [/tex]
[tex]x^{2} + 10x - 24 = 0 [/tex]
[tex]x = \frac{- 10 +- \sqrt{10^{2}- 4 x 1 x 24}} {2}[/tex]
[tex]x = \frac{- 10 + 2} {2} = -4[/tex]
[tex]x = \frac{- 10 - 2} {2} = -6[/tex]
[tex]x = -6[/tex]
[tex]x = -4[/tex]
[tex]x = 0[/tex]
f(x) = x^3 –+10x^2 + 24x
x^3+ 10x^2 + 24x = 0
x(x^2+10x+24) = 0
x(x+4)(x+6) = 0
x= 0 or x = -4 or x =- 6
so the correct answer is C
hope it helps
x^3+ 10x^2 + 24x = 0
x(x^2+10x+24) = 0
x(x+4)(x+6) = 0
x= 0 or x = -4 or x =- 6
so the correct answer is C
hope it helps