Answer:
3.02 atm
Explanation:
Step 1: Given data
- Initial pressure (P₁): 1.36 atm
- Initial volume (V₁): 4.24 × 10² mL
- Initial temperature (T₁): 25 °C
- Final volume (V₂): 1.91 × 10² mL
- Final temperature (T₂): 25 °C
Step 2: Find the final pressure
Since the temperature is constant, we can find the final pressure using Boyle's law.
[tex]P_1 \times V_1 = P_2 \times V_2\\P_2 = \frac{P_1 \times V_1}{V_2} = \frac{1.36atm \times 4.24 \times 10^{2}mL }{1.91 \times 10^{2}mL} = 3.02 atm[/tex]
