Respuesta :

HomertheGenius
As we know that:
[tex] \lim_{n \to 0} \frac{sinn}{n}=1 [/tex]
[tex] \lim_{x \to 0} \frac{sin2x}{4x}: \frac{2}{2}= \\ \frac{1}{2} \lim_{x \to 0} \frac{sin2x}{2x} = \frac{1}{2}*1 = \frac{1}{2} [/tex]

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