Answer:
x=9√10
solution,
[tex] {y}^{2} = 3 \times 27 \\ {y}^{2} = 81 \\ y = \sqrt{81} \\ y = \sqrt{ {9}^{2} } \\ y = 9 \\ \\ {y}^{2} + {27}^{2} = {x}^{2} \\ or \: {9}^{2} + {27}^{2} = {x}^{2} \\ or \: 81 + 729 = {x}^{2} \\ or \: 810 = {x}^{2} \\ or \: x = \sqrt{810} \\x = 9 \sqrt{10} [/tex]
hope this helps...
Good luck on your assignment..
