contestada

Which of the following shows the graph of y = 2 l n x On a coordinate plane, a curve starts at (0, negative 2) in quadrant 4 and then increases into quadrant 1 and approaches y = 3. On a coordinate plane, a curve starts in quadrant 4 and then curves up into quadrant 1 and approaches y = 5. It crosses the x-axis at (1, 0). On a coordinate plane, a curve approaches the y-axis in quadrant 2 and then increases into quadrant 1. It crosses the y-axis at (0, 1). On a coordinate plane, a curve approaches the y-axis in quadrant 2 and then increases into quadrant 1. It crosses the y-axis at (0, 2).

Respuesta :

Answer:

The answer to this question can be defined as follows:

Step-by-step explanation:

Given:

[tex]f(x)= 2^{-x}=\frac{1}{2^x}[/tex]

  • In the above choices it is clearly defined from the above equation that output rises in the first quadrant, the value of f(x) tends to be zero and increases into another second quadrant.
  • For x = 0, y, once again, has become 1, that is the function passes the y platform at (0,1).
  • Therefore an exponential function reaches y = 0 in quadrant 1 on a coordinate plane and rises into quadrant 2.
  • (0,1) stage is the temperature at which the y-axis intersects.
MrRoyal

The graph of y = 2ln(x) is (b) on a coordinate plane, a curve starts in quadrant 4 and then curves up into quadrant 1 and approaches y = 5. It crosses the x-axis at (1, 0).

How to determine the graph of the equation?

The equation of the graph is given as:

[tex]y = 2\ln(x)[/tex]

Start by plotting the graph of [tex]y = 2\ln(x)[/tex] .

From the graph (see attachment), we have the following highlights

  • The curve of the graph starts at the 4th quadrant
  • It moves up to the 1st quadrant
  • It crosses the x-axis at x = 1, and it approaches y = 5

From the list of given options, only option (b) describes the above highlights

Hence, the graph of y = 2ln(x) is (b)

Read more about graphs and functions at:

https://brainly.com/question/3939432

Ver imagen MrRoyal

Otras preguntas

Q&A Education