Answer:
The work will be "1909212.015 J". The further explanation is given below.
Step-by-step explanation:
The given values are:
Liquid's density
= 760 kg/m³
Height
= 3 meters
Gravity
g = 3.8 m/s²
Value of y is:
y = 5 log (x-2)
y = 0
y = 4
As we know,
⇒ [tex]\Delta V=\pi r^2 \Delta y[/tex]
⇒ [tex]y =5log(x-2)[/tex]
⇒ [tex]\frac{y}{5} =log (x-2)[/tex]
⇒ [tex]e^{\frac{y}{5}}=(x-2)[/tex]
⇒ [tex]x=e^{\frac{y}{5}}+2[/tex]
Now,
[tex]\Delta F=ma[/tex]
[tex]=760 \pi (e^{\frac{y}{5}}+2)^2(9.8)\Delta y[/tex]
So that,
⇒ [tex]\Delta W = \Delta F.distance[/tex]
[tex]=\Delta F(4-y)[/tex]
The required work will be:
⇒ [tex]W=760\times 9.8 \pi \int_{3}^{0}(e^{\frac{y}{5}}+2)^2 (\Delta-y)dy[/tex]
[tex]=760\times 9.8 \pi[{-20(y-9)^{e^{\frac{y}{5}}}-2(y-8)y}][/tex]
[tex]=760\times 9.8 \pi[81.455][/tex]
[tex]=1909212.015 \ J[/tex]
