Answer:
0.5 or 50%
Step-by-step explanation:
- Total number of championships won = 3+2+1+7+2+1=16
- Total Number of winners in baseball league, n(B)= 3+2+1=6
- Number of Wins in the Ages 10 - 12 division, n(Y) =2
- Number of Wins in the Ages 13-15 division, n(Z) =1
The probability that the winning team is in the Ages 10 - 12 division given that it is in the baseball league:
[tex]P(Y|B)=\dfrac{P(Y \cap B)}{P(B)} \\=\dfrac{2/16}{6/16}\\=\dfrac{2}{6}[/tex]
The probability that the winning team is in the Ages 13 - 15 division given that it is in the baseball league:
[tex]P(Z|B)=\dfrac{P(Z \cap B)}{P(B)} \\=\dfrac{1/16}{6/16}\\=\dfrac{1}{6}[/tex]
Therefore:
[tex]P(Y$ or $Z|B)=\dfrac{2}{6}+\dfrac{1}{6}\\=\dfrac{3}{6}\\\\=0.5[/tex]
