Answer:
inside the circle
Step-by-step explanation:
The radius is sqrt(38)
The distance from the center to the point is
d = sqrt( ( y2-y1) ^2 + ( x2 -x1) ^2)
= sqrt( ( 1 - 0)^2 + ( 6 - 0 ) ^2)
= sqrt( (1^2 + 6^2)
= sqrt( 1+36)
= sqrt(37)
This is less than the radius so the point is inside the circle
