Answer:
mass of ethanolamine 61.2 g
Explanation:
Data:
V (Volume) = 60 mL
ρ (Density)= 1.02 [tex]\frac{g}{cm^{3} }[/tex] = 1.02 [tex]\frac{g}{mL}[/tex]
With the given data and using the density formula:
ρ = [tex]\frac{mass}{volume}[/tex]
It is possible to calculate the grams of ethanolamine that the student should weigh out. The mass in the formula is cleared and the data is replaced.
mass = ρ * volume
mass = 1.02 [tex]\frac{g}{mL}[/tex] * 60 mL = 61.2 g of ethanolamine
