The ideal mass for a piece of chocolate is 2.5 ounces. The actual mass for a production can vary by, at most, 0.08
ounces. Create an absolute value inequality and solve it to determine the range of chocolate masses.​

Respuesta :

Answer:

[tex]2.42\,oz \leq m_{real} \leq 2.58\,oz[/tex]

Step-by-step explanation:

The inequality must be the absolute value of the difference between real mass and ideal mass less or equal to 0.08 ounces. That is to say:

[tex]|m_{real} - m_{ideal}| \leq 0.08\,oz[/tex]

[tex]|m_{real} - 2.5\,oz| \leq 0.08\,oz[/tex]

There are two extreme cases:

[tex]m_{real,max} - 2.5\,oz = 0.08\,oz[/tex] and [tex]m_{real, min} - 2.5\,oz = -0.08\,oz[/tex]

[tex]m_{real, max} = 2.58\,oz[/tex] and [tex]m_{real,min} = 2.42\,oz[/tex]

Range of chocolate masses must be:

[tex]m_{real, min} \leq m_{real} \leq m_{real,max}[/tex]

[tex]2.42\,oz \leq m_{real} \leq 2.58\,oz[/tex]

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