Answer:
[tex]2.42\,oz \leq m_{real} \leq 2.58\,oz[/tex]
Step-by-step explanation:
The inequality must be the absolute value of the difference between real mass and ideal mass less or equal to 0.08 ounces. That is to say:
[tex]|m_{real} - m_{ideal}| \leq 0.08\,oz[/tex]
[tex]|m_{real} - 2.5\,oz| \leq 0.08\,oz[/tex]
There are two extreme cases:
[tex]m_{real,max} - 2.5\,oz = 0.08\,oz[/tex] and [tex]m_{real, min} - 2.5\,oz = -0.08\,oz[/tex]
[tex]m_{real, max} = 2.58\,oz[/tex] and [tex]m_{real,min} = 2.42\,oz[/tex]
Range of chocolate masses must be:
[tex]m_{real, min} \leq m_{real} \leq m_{real,max}[/tex]
[tex]2.42\,oz \leq m_{real} \leq 2.58\,oz[/tex]