Let θ be an angle in quadrant IV such that sinθ=-3/4. Find the exact values of secθ and cotθ.
cos2(θ) + sin2(θ) = 1
sec(θ) = 1/cos(θ)
cot(θ) = cos(x)/sin(θ)
sin(θ) = -3/4
cos2(θ) + sin2(θ) = 1
cos2(θ) = 1 - sin2(θ)
cos2(θ) = 1 - 9/16 = 7/16
cos(θ) = ±√(7/16) = √7/16 (cosine is positive in Q IV)
sec(θ) = 1/cos(θ) = 4/√7
cot(θ) = cos(θ)/sin(θ) = (4/√7)/(-3/4) = -16√7/21
The exact values of secθ = 4/√7 and cotθ = -16√7/21
Trigonometric functions defined as the functions which show the relationship between angle and sides of a right-angled triangle.
Given that,
sinθ = -3/4
∵sin²(θ) +cos²(θ) = 1
∴cos²(θ) = 1 - sin²(θ)
cos(θ) = √(1 - sin²(θ))
cos²(θ) = √(1 - 9/16 )
cos(θ) = ±√(7/16) = √7/4 (cosine is positive in quadrant IV )
sec(θ) = 1/cos(θ) = 4/√7
∵cot(θ) = cos(θ)/sin(θ)
∴cot(θ)= (4/√7)/(-3/4)
cot(θ) = -16√7/21
The exact values of secθ = 4/√7 and cotθ = -16√7/21
Learn more about Trigonometric functions
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