The composition transformation process is from ABCD to A'B'C'D', then
to A''B''C''D''.
Correct response:
- The composition transformation is; [tex]\underline{T_{-6, \, 1} \ \circ \ r_{x - axis}(x, \, y)}[/tex]
Process used for finding the composition transformation
The given coordinates of the pre-image ABCD are;
A(3, 5), B(6, 5), C(4, 1), D(1, 1).
The coordinates of the image D'C'A'B' are;
A'(3, -5), B'(6, -5), C'(4, -1), and D'(1, -1).
Therefore, the rule that gives the coordinates of A'B'C'D' from ABCD
(x, y) [tex]\underrightarrow{Rule}[/tex] (x, -y)
The rule for a reflection across the x-axis is; (x, y) [tex]\underrightarrow{r_{x-axis}}[/tex] (x, -y)
Therefore;
The rule that gives A'B'C'D', from ABCD is a reflection across the x-axis.
The rule that gives A''B''C''D'' from A'B'C'D' is the a translation 6 units left and 1 unit up, which is; [tex]\mathbf{T_{-6, \, 1}}[/tex]
Therefore composition transformation that maps pre-image ABCD to
final image A''B''C''D'' is given by a reflection followed by a translation,
with the second transformation coming first in the expression as follows;
- [tex]\underline{T_{-6, \, 1} \ \circ \ r_{x-axis}(x, \, y)}[/tex]
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