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What is the kinetic energy,in J,of an Ar atom moving at a speed of 650 m/s

Respuesta :

Answer:

1.40 × 10⁻²⁰ J

Explanation:

Step 1: Calculate the mass of 1 atom of argon

The molar mass of argon is 39.95 g/mol, that is, 6.02 × 10²³ atoms of Ar have a mass of 39.95 g. We can use this relation to find the mass of 1 atom of Ar.

[tex]\frac{39.95g}{1mol} \times \frac{1mol}{6.02 \times 10^{23}atom } =6.64 \times 10^{-23}g/atom[/tex]

Step 2: Convert the mass of 1 atom of argon to kilograms

We will use the relationship 1 kg = 1,000 g.

[tex]6.64 \times 10^{-23}g \times \frac{1kg}{1,000g} =6.64 \times 10^{-26}kg[/tex]

Step 3: Calculate the kinetic energy of 1 atom of Ar moving at 650 m/s

[tex]E=\frac{1}{2} \times m \times v^{2} = \frac{1}{2} \times 6.64 \times 10^{-26}kg \times (650m/s)^{2} = 1.40 \times 10^{-20}J[/tex]

The kinetic energy of an Ar atom at a speed of 650 m/s is 1.40 × 10⁻²⁰ J

Kinetic Energy:

Kinetic energy is directly proportional to the mass of the object and to the square of its velocity:

K.E = [tex]\frac{1}{2}[/tex] x [tex]m[/tex] x [tex]v^{2}[/tex]

Step 1: Calculate the mass of 1 atom of argon

The molar mass of argon is 39.95 g/mol, that is, 6.02 × [tex]10^{-23}[/tex] atoms of Ar have a mass of 39.95 g. We can use this relation to find the mass of 1 atom of Ar.

[tex]\frac{39.95 g}{1 mol} * \frac{1 mol}{1,000 g} = 6.64 * 10^{-26} g/ atom[/tex]  

Step 2: Convert the mass of 1 atom of argon to kilograms

We will use the relationship 1 kg = 1,000 g.

6.64 x [tex]10^{-23}[/tex] g x [tex]\frac{1 kg}{1,000g}[/tex] = 6.64 x [tex]10^{-26}[/tex] kg

Step 3: Calculate the kinetic energy of 1 atom of Ar moving at 650 m/s

E= [tex]\frac{1}{2}[/tex] x [tex]m[/tex] x [tex]v^{2}[/tex] = [tex]\frac{1}{2}[/tex] x 6.64 x [tex]10^{-26}[/tex] kg x (650 m/s)² = 1.40 x [tex]10^{-20}[/tex] J

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