A. Suppose the laser light has wavelength 400 nm, and that the two small slits, which act as point sources of light, are separated by 0.1 mm. (Recall that 1 nm = 10-9 meters.) Approximately how many nodal lines would be present in the pattern of overlapping light waves when the laser light emerges from the two slits in the mask?

Respuesta :

Answer:

200 nodal lines

Explanation:

To find the number of lines you first use the following formula for the condition of constructive interference:

[tex]dsin\theta=m\lambda[/tex]  (1)

d: distance between slits = 0.1mm = 0.1*10^-3 m

θ: angle between the axis of the slits and the m-th fringe of interference

λ: wavelength of light = 400 nm = 400*10^-9 m

You obtain the max number of lines when he angle is 90°. Then, you replace the angle by 90° and solve the equation (1) for m:

[tex]dsin90\°=m\lambda\\\\d=m\lambda\\\\m=\frac{d}{\lambda}=\frac{0.1*10^{-3}m}{500*10^{-9}m}=200[/tex]

hence, the number of lines in the interference pattern are 200

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