Please give an accurate answer and show work.
Answer:
3.06
Step-by-step explanation:
[tex]\log_{5}(\dfrac{2}{3}x-2)+2=0\\\\\log_{5}(\dfrac{2}{3}x-2)=-2\\\\[/tex]
This means that 5 to the power of -2 is [tex](\dfrac{2}{3}x-2)[/tex], meaning that:
[tex]\dfrac{2}{3}x-2=5^{-2}=\dfrac{1}{25} \\\\\dfrac{2}{3}x=\dfrac{51}{25} \\\\2x=\dfrac{153}{25} \\\\x=\dfrac{153}{50}=3.06[/tex]
Hope this helps!